std::chrono::year_month_weekday_last::operator+=,(3)

NAME
std::chrono::year_month_weekday_last::operator+=, - std::chrono::year_month_weekday_last::operator+=,

Synopsis
   constexpr std::chrono::year_month_weekday_last& (1) (since C++20)
   operator+=( const std::chrono::years& dy ) const noexcept;
   constexpr std::chrono::year_month_weekday_last& (2) (since C++20)
   operator+=( const std::chrono::months& dm ) const noexcept;
   constexpr std::chrono::year_month_weekday_last& (3) (since C++20)
   operator-=( const std::chrono::years& dy ) const noexcept;
   constexpr std::chrono::year_month_weekday_last& (4) (since C++20)
   operator-=( const std::chrono::months& dm ) const noexcept;
   Modifies the time point *this represents by the duration dy or dm.
   1) Equivalent to *this = *this + dy;
   2) Equivalent to *this = *this + dm;
   3) Equivalent to *this = *this - dy;
   4) Equivalent to *this = *this - dm;
   For durations that are convertible to both std::chrono::years and
   std::chrono::months, the years overloads (1,3) are preferred if the call would
   otherwise be ambiguous.

Example
// Run this code
 #include <iostream>
 #include <chrono>
 using namespace std::chrono;
 int main()
 {
     std::cout << std::boolalpha;
     auto ymwdl {August/Tuesday[last]/2022};
     ymwdl += months(2);
     std::cout << (year_month_day{ymwdl} == October/25/2022) << ' ';
     ymwdl -= years(1);
     std::cout << (year_month_day{ymwdl} == October/26/2021) << '\n';
 }

Output:
 true true

See also
   operator+ adds or subtracts a year_month_weekday_last and some number of years or
   operator- months
   (C++20) (function)