std::chrono::year_month_weekday_last::operatorsys_days,(3)

NAME
std::chrono::year_month_weekday_last::operatorsys_days, - std::chrono::year_month_weekday_last::operatorsys_days,

Synopsis
   constexpr operator std::chrono::sys_days() const noexcept; (1) (since C++20)
   explicit constexpr operator std::chrono::local_days() const (2) (since C++20)
   noexcept;
   Converts *this to a std::chrono::time_point representing the same date as this
   year_month_weekday_last.
   1) If ok() is true, returns a sys_days that represents the last weekday() of the
   year() and month(). Otherwise, the returned value is unspecified.
   2) Same as (1), but returns local_days instead of sys_days. Equivalent to
   local_days(sys_days(*this).time_since_epoch()).

Example
// Run this code
 #include <iostream>
 #include <chrono>
 using namespace std::chrono;
 int main()
 {
     std::cout << std::boolalpha;
     constexpr auto ymwdl {Tuesday[last]/11/2021};
     static_assert(static_cast<local_days>(ymwdl) ==
                   static_cast<local_days>(November/30/2021));
     // convert from field-based to serial-based to add days
     constexpr auto sd = static_cast<sys_days>(ymwdl);
     constexpr year_month_day ymd {sd + days(10)};
     std::cout << (ymd == December/10/2021) << '\n';
 }

Output:
 true