pyspark.pandas.Index.rename

Index.rename(name: Union[Any, Tuple[Any, …], List[Union[Any, Tuple[Any, …]]]], inplace: bool = False) → Optional[pyspark.pandas.indexes.base.Index]

Alter Index or MultiIndex name. Able to set new names without level. Defaults to returning new index.

Parameters

namelabel or list of labels

Name(s) to set.

inplaceboolean, default False

Modifies the object directly, instead of creating a new Index or MultiIndex.

Returns

Index or MultiIndex

The same type as the caller or None if inplace is True.

Examples

>>> df = ps.DataFrame({'a': ['A', 'C'], 'b': ['A', 'B']}, columns=['a', 'b'])
>>> df.index.rename("c")
Int64Index([0, 1], dtype='int64', name='c')

>>> df.set_index("a", inplace=True)
>>> df.index.rename("d")
Index(['A', 'C'], dtype='object', name='d')

You can also change the index name in place.

>>> df.index.rename("e", inplace=True)
>>> df.index
Index(['A', 'C'], dtype='object', name='e')

>>> df  
   b
e
A  A
C  B

Support for MultiIndex

>>> psidx = ps.MultiIndex.from_tuples([('a', 'x'), ('b', 'y')])
>>> psidx.names = ['hello', 'pandas-on-Spark']
>>> psidx  
MultiIndex([('a', 'x'),
            ('b', 'y')],
           names=['hello', 'pandas-on-Spark'])

>>> psidx.rename(['aloha', 'databricks'])  
MultiIndex([('a', 'x'),
            ('b', 'y')],
           names=['aloha', 'databricks'])

pyspark.pandas.Index.map pyspark.pandas.Index.repeat